Q&A: What is the electric field strength of a 76 cm diameter loop?

by The Library of Congress

Question by physickzguru: What is the electric field strength of a 76 cm diameter loop?

A 76 cm diameter loop is rotated in a uniform
electric field until the position of maximum
electric flux is found. The flux in this position
is measured to be 3.12 × 105 N · m2/C.
What is the electric field strength?
Answer in units of N/C.




Best answer:

Answer by DH
Flux Φ = E*A so E = Φ/A = 3.12x10^5/(π*(0.38m)^2) = 6.88x10^5N/C

Give your answer to this question below!